Three resistors 5 Ohm, 10 Ohm and 20 Ohm are connected in
parailel across potential difference 12V. Find the total current
flows in the circuit.
Answers
Answer:
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Explanation:
Answer:
A ] 5Ω = 1.2 Ampere , 10Ω = 0.6 Ampere , 30Ω = 0.2 Ampere
B ] I = 2 Ampere
C ] R = 3Ω
Explanation:
★ CURRENT ELECTRICITY ★
★ GIVEN ;
» 3 RESISTANCE = 5Ω , 10Ω and 30Ω connected in Parallel.
» EMF OF CELL = 6 VOLT
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A ] CURRENT THROUGH EACH RESISTOR .
» As ; all are connected in PARALLEL .. SO ; POTENTIAL DIFFERENCE ACROSS ALL RESISTORS IS SAME .
★ I¹ ( Current in 5Ω Resistor ) = V / R = 6 / 5 = 1.2 Ampere.
★ I² ( Current in 10Ω Resistor ) = V / R =
V / R = 6 / 10 = 0.6 Ampere
★ I³ ( Current in 30Ω Resistor ) = V / R =
V / R = 6 / 30 = 0.2 Ampere .
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B ] TOTAL CURRENT IN CIRCUIT.
» Equivalent Resistance of 3 Resistors in Parallel is ;
1 / R = 1 / R¹ + 1 / R² + 1 / R³
= 1 / 5 + 1 / 10 + 1 / 30
= [6 + 3 + 1 / 30 ]
1 / R = 10 / 30
★ R = 30 / 10 = 3Ω .
[ TOTAL CURRENT ( I ) = V / R = 6 / 3 = 2 AMPERE ] .
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C ] EFFECTIVE RESISTANCE
R = 3 Ω .
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