Question

Three resistors 5ohm,10 ohm,3ohm are connected in parallel with the battery of voltage 6V effective resistance of the circuit

Answer 1

Explanation:

Answers

SerenaBochenek Ambitious

As per the question, three resistors are connected in parallel.

Let\ R_{1}\ ,R_{2}\ and\ R_{3} are the three resistors.

Let\ R_{1} =5 ohm

R_{2} =10ohm

R_{3} =30ohm

The voltage of battery V= 6 volt.

Let the equivalence resistance is R.

As these are connected in parallel, then-

\frac{1}{R} =\frac{1}{R_{1}} +\frac{1}{R_{2}} +\frac{1}{R_{3}}

=\frac{1}{5} +\frac{1}{10} +\frac{1}{30}

=\frac{6+3+1}{30}

=\frac{10}{30}

Hence\ R=\frac{30}{10} \ ohm

= 3 ohm

Now we are asked to calculate the current in each resistor.

The net current flowing through the circuit is-

i=\frac{V}{R}

=\frac{6}{3}\ A

=2\ A

The current in 5 ohm will be = \frac{6}{5} \ A

=1.2 A

The current in 10 ohm will be =\frac{6}{10}\ A

=0.6 A

The current in 30 ohm will be =\frac{6}{30}\ A

=0.2 A

Here, A is the unit of current called ampere.

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Answer 2

Correct question:- Three resistors 5ohm,10 ohm,3ohm are connected in parallel with the battery of voltage 6V effective resistance of the circuit then find the equivalent resistance.

Given:- Three resistors of 5ohm, 10ohm &3ohm also these resistors are connected in parallel in the circuit and have the voltage of 6V.

Let us assume that R1 , R2 & R3 are the three resistors

Where R1= 5 ohm

R2=10 ohm

R3=3 ohm

And let voltage of the battery be V= 6 volt

Let the required or the equivalent resistance be 'R'.

We know, for parallel connection we have,

→1/R= 1/R1+ 1/R2+1/R3

→1/R= 1/5 + 1/10 +1/3

→1/R= 6+3+10/30

→1/R= 19/30

→R= 0.6333 (approx.)

Hence, the equivalent resistance of the circuit will be 0.633 .