Question

Three resistors are arranged in a circuit as shown in figure. The voltage-current
graph of three resistors are given below. The ratio of current flowing in the circuit
when switch Sis closed to switch Sis opened, is
तीन प्रतिरोधकों को चित्रानुसार एक परिपथ में व्यवस्थित किया जाता है। तीनों प्रतिरोधकों के
वोल्टता-धारा आरेख नीचे दिये गए हैं। जब स्विच Sबन्द है तथा जब स्विच खुला है, तब इन दोनों
स्थितियों में परिपथ में प्रवाहित धारा का अनुपात है
R,
N
R
m
S
120V.
45°
30
60
N​

Answer 1

Given : Three resistors are arranged in a circuit as shown in figure. The voltage-current graph of three resistors are  given

To Find : . The ratio of current flowing in the circuit when switch S is closed to switch S is opened,​

Solution:

R = V/I

Hence slope of graph will give resistance value

R₁ = Tan 30°  = 1/√3

R₂ = Tan 60°  = √3

R₃ = Tan 45°  = 1

When Switch S closed R₁  ║ R₃

1/R = 1/(1/√3) + 1/1

=> 1/R = √3 +  1

=> R = 1/(√3 +  1 )

=> R = (√3 -  1)/2

R₂ is in series

So Net R  =  (√3 -  1)/2 + √3   =  (3√3 - 1)/2

I = V/R  = 120/  (3√3 - 1)/2   = 240 / (3√3 - 1)

240 (3√3 + 1)/26

= 120(3√3 + 1)/13

when Switch S is open  R₁  and R₂ are in series

Net R =  1/√3  + √3   = (1 + 3)/√3  =  4/√3

I = V/R  =  120/ 4/√3   = 30√3

120(3√3 + 1)/13  : 30√3

=  4 (3√3 + 1) : 13√3

=  24.785 : 22.517

= 1.101 : 1

= 1.1  : 1

Learn More:

on the basis of laws of series and parallel resistances,prove that the ...

https://brainly.in/question/18904705

Two resistors of resistance 1.0 Ω and 2.0 Ω connected in parallel are ...

https://brainly.in/question/18350094