Question

Three resistors are connected as shown in Fig. 1.37. Through the resistor of 5 2, a
current of 1 A is flowing.
(a) Find the potential difference across AB and across AC.
(b) Calculate the current across the other two resistors.
(C)What is the total resistance ?

answer fastly​

Answer 1

Answer:

potential difference ( v ) = R × I

POTENTIAL DIFFERENCE ACROSS AB=

RESISTANCE (R) = 5 OHMS

CURRENT (I) = 1 AMPERE

SO

V = 1×5

•) V= 5 VOLTS

NOW , ACROSS AC

RESISTANCE (R) = ??

CURRENT (I) = 1

now for total resistance =

by parallel law -

1/Rp = 1/R2 + 1/R3

1/Rp = 1/10 + 1/15

1/Rp =( 3 + 2)/ 30

Rp = 30 / 5 = 6 ohms ------------ eq 1

now by series law ( from eq 1 )

Rs = R1 + Rp

Rs = 5 + 6

Rs = 11 ohms -------------eq 2

now by eq 2

VOLTAGE ACROSS AC =

11 × 1 = 11 volts

B) now voltage across R2 AND R3

BY EQUATION 1

RESISTANCE= 5 OHMS

CURRENT = 1 AMPERE

HENCE

VOLTAGE = 5 × 1

= 5 volts

now

c) total resistance = 11 ohms ( from eq 2)

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# Question repeated....

Answer 2

Answer:

V = I × R = 1 × 5 = 5V

a)

1/Req = 1/10 + 1/15

1/Req = 5/30

Req = 6

Now, I = V/R

= 5/6

= 0.8 A

b) potential difference across A and B

dv = (5 - 0)

dv = 5 volt

potential difference across A and C

dv = { 5 + (0.8 × 6) - 0}

dv = 9.8 volt

c)

total resistance = 5 + 6 = 11 Ω

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