Question

three resistors are connected as shown in figure through the resistor of 5 ohm a current of 1ohm is flowing​

Answer 1

Explanation:

Given,

Current in AC, IAC=1A

 Resistance in BC, RBC=10+1510×15=6Ω

Current flowing in series  IAB=IBC=1A

VBC=IBC×RBC=1×6=6V

In parallel potential is equal

VBC=I10R10=I15R15=6

(a)    I10=106=0.6A,  I15=150.6=0.4A

(b)    Potential in AB VAB=IABRAB=1×5=5V., VBC=IBCR