Question

Three resistors are connected as shown in the figure. Through the resistor 5 ohms a constant current of 1 ampere is flowing. Find the current through 10 ohm resistor.
1 point
Captionless Image
(a) 0.6 A
(b) 0.4 A
(c) 1.2 A
(d) 2.0 A​

Answer 1

ANSWER

Given,

Current in AC, I

AC

=1A

Resistance in BC, R

BC

=

10+15

10×15

=6Ω

Current flowing in series I

AB

=I

BC

=1A

V

BC

=I

BC

×R

BC

=1×6=6V

In parallel potential is equal

V

BC

=I

10

R

10

=I

15

R

15

=6

(a) I

10

=

10

6

=0.6A, I

15

=

15

0.6

=0.4A

(b) Potential in AB V

AB

=I

AB

R

AB

=1×5=5V., V

BC

=I

BC

R

BC

=1×6=6V

(c) Total Resistance R

total

=R

AC

+R

BC

=5Ω+6Ω= 1 2 A

Explanation:

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