Three resistors are connected in parallel with a 30V battery. A current of 7.5A flows through the circuit. If two out of the three resistors are of 10ohm and 12ohm, determine the resistence of the third resistor.
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Equivalent resistance = V / i
= 30 V / (7.5 A)
= 4 Ω
In parellel arrangement
1/Req = 1/R₁ + 1/R₂ + 1/R₃
1/R₃ = 1/Req - (1/R₁ + 1/R₂)
1/R₃ = 1/4 - (1/10 + 1/12)
R₃ = [1/4 - (1/10 + 1/12)]^-1
R₃ = 15 Ω
Resistance of third resistor is 15 Ω
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