three resistors are connected in series to 24 volt battery , and an ammeter in the circuit reads 0.50 amperes . the first resistor is rated at 22 ohms, and the second at 8 ohms . find the (a ) the total resistance (b) the resistance of the third resistor , and (c) the potential difference across the third resistor .
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I = 0.50A
V = 24V
(a) Total resistance = V/I
=24/0.50
= 48 ohms
(b) R3 = R - R1-R2
=48 -22-8
=18 ohms
(c) V across R3 = I×R3
= 0.50×18
= 9 V
V = 24V
(a) Total resistance = V/I
=24/0.50
= 48 ohms
(b) R3 = R - R1-R2
=48 -22-8
=18 ohms
(c) V across R3 = I×R3
= 0.50×18
= 9 V
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