Three resistors are connected to a cell of potential difference 12V as shown in
this diagram,
Calculate,
(i) the total current.
(ii) the voltage across 2 Ω resistor.
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Answer:
Given , V = 12
We find,
(i) the total current.
(ii) the voltage across 2 Ω resistor.
So, firstly we find total resistance in the circuit
From the diagram two resistance are connected in parallel.
Rp = 4/2 = 2Ω
And then this resistance are connected with one resistance in series
Rs = 2Ω + 2Ω = 4Ω.
By ohms law,
I =V/R
I = 12/4
I = 3A
(ii) Now, we find Potential difference across 2Ω Resistance.
2Ω resistor is connected in series.
Therefore , current is same , i.e., 3A
Resistance = 2Ω
By ohms law,
V = IR
V = 3×2
V = 6v
Hope it helps you.
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