Three resistors each of 9Ω to be connected in which way to get a resultant resistance of 6.25Ω.
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Explanation:
U can't get 6.25 but can get 6 ohms.
First, connect 2 resistors in series, so R=9+9=18ohms.
Now, connect this R to other 9 ohm in Parallel.
So, 1/(R(net))=(1/9)+(1/18)
R(net)=18x9/(18+9)=18x9/27=6 ohms
So, net resistance is 6 ohms.
Thank you
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