three resistors each of resistance 7.5 ohm are connected in parallel find resistor for each of 8 are connected in parallel and other three resistors each of resistance 6 are in parallel if these three parallel combination are in series find the effective resistance of the circuit
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Answer:
7.2 ohm
Explanation:
When three resistors of 7.5 ohm are connected in parallel then r equivalent is
1/r = 1/r1 + 1/r2 +1/r3
r =r/3. (as r1,r2,r3 is same)
So, r=7.5/3=2.5
Similarly for 8 ohm resistors
r=8/3=2.7
and for 6 ohm resistor
r=6/2=2.
Now these three parallel connections are connected in series so their equivalent resistance will be there sum which is
R1+ R2+ r3=2.5+2.7+2=7.2
Therefore the equivalent resistance of the circuit will be 7.2 ohm.
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