three resistors each of value (r) connected as three side of a triangle the equivalent resistance across its any two vertices is?
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Let, 3 resistors are connected to form the sides of a triangle, the resistance of the sides AB, BC and CA are 40 ohms, 60 ohms and 100 ohms respectively.
Let, 40ohm and 60 ohm are in series so,
R = R(ac) + R (cb), R = 100 + 60, R = 160 ohm ( 1 ), the R is parallel to 40 ohm. Therefore, 1 / R = 1 / 40 + 1 / 160 or, 1 / R = 5 / 160 or, R = 160/5 or, R = 32 ohm.
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