Question

Three resistors having resistance 4 ohm 2 ohm and 6 ohm are connected in parallel. Find net resistance in the circuit.​

Answer 1

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1/Net resistance = 1/4 + 1/2 + 1/6Ω

= 3+6+2/12 Ω

= 10/12 Ω

=> Resistance = 12/10Ω = 1.2Ω

Answer 2

Given :

• Three resistors having resistance 4 ohm , 2 ohm and 6 ohm are connected in parallel connection.

To find :

• Net resistance in the circuit ( or equivalent resistance)

Formula used:

$\dfrac{1}{Req} = \dfrac{1}{R1} + \dfrac{1}{R2} + \dfrac{1}{R3} ......$

The above Formula is for parallel connection only.

where:-

• Req = Equivalent resistance

Solution :

let R1 = 4 ohm , R2 = 2 ohm , R3 = 6 ohm

Now put above values in the formula to get the value of Req :-

$\dfrac{1}{Req} = \dfrac{1}{4} + \dfrac{1}{2} + \dfrac{1}{6}$

LCM of 4,2and6 = 12

$\implies\dfrac{1}{Req} = \dfrac{3 + 6 + 2}{12}$

$\implies\dfrac{1}{Req} = \dfrac{11}{12}$

$\implies \: Req = \dfrac{12}{11}$

Answer :-

• Net resistance or Equivalent resistance = 12/11