Question

Three resistors having resistance of 5 Ω 12 Ω and 6 Ω are connected in series what is the effective resistance in the circuit

Answer 1

Answer:

1/Reff=1/R1+1/R2+1/R3+1/R4+1/Rn

1/R eff =1/15+1/20+1/10×(1/2)=13/60

R eff=60/15

=4.615Ω

i hope it will help u...

Answer 2

Its in series so just add all values
5+12+6=23ohm