Question

Three resistors having resistance of 5ohms,10and 30ohms. Are connected in parallel and potintial difference of 12v is applied then obtained the current flowing through the circuit?

Answer 1

when registers are connected in parallel than
1/Req = 1/R1+ 1/R2 +1/R3
= 1/5+ 1/10 + 1/30
= 6+3+1/30
= 10/30 = 1/3
hence Req = 3ohm

now current = V /R = 12/3 = 4 amp

Answer 2

1/RP=1/R1+1/R2+1/R3
=1/5+1/10+1/30
=6+3+1/30
=0.33 ohms
I=12/0.33
I=400/11