Question

Three resistors in series have a total resistance RT of 2.7 kΩ. If R2 is twice the value of R1 and R3 is three times the value of R2 , what are the values of R1 , R2 , and R3 ?
ANSWER IN DETAIL....

Answer 1

Answer:

RT=R1+R2+R3

let R1=x

so,R2=2×R1=2x and R3=3(R2)=3(2x)=6x

so, 2,700=x+2x+6x

2,700=9x

x=2,700/9

x=300

so,R1=x=300ohm

R2=2x=2(300)=600ohm

R3=6x=6(300)=1800ohm

hope it will help you.