Three resistors in series have an RT of 7 kΩ. If R3 is 2.2 times larger than R1 and 1.5 times larger than R2, what are the values of R1 , R2 , and R3 ? ANSWER IN DETAIL.....
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Answer:
R₁ = 1.272 kΩ
R₂ = 1.628 kΩ
R₃ = 4.072 kΩ
Explanation:
If 3 resistors are connected in series, then their equivalent resistance will be the product of each resistance.
∴ R₁ + R₂ + R₃ = 7 kΩ
Given,
- R₃ = 2.2R₁ + R₁ = 3.2R₁
- R₃ = 1.5R₂ + R₂ = 2.5R₂
(R₃/3.2) + (R₃/2.5) + R₃ = 7
(2.5R₃ + 3.2R₃ + 8R₃)/8 = 7
R₃ = 56/13.75 = 4.072 kΩ
R₂ = 1.628 kΩ
R₁ = 1.272 kΩ
∴ ,
- R₁ = 1.272 kΩ
- R₂ = 1.628 kΩ
- R₃ = 4.072 kΩ
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