Question

Three resistors of 1 Ω, 2Ω and 3 Ω are connected in parallel. The combined resistance of the three resistors will be

Select one:
a. Less than 1 Ω
b. Greater than 3 Ω
c. Equal to 2 Ω
d. Between 1 Ω and 3 Ω Correct

Answer 1

Answer:

a. Less than 1Ω

Explanation:

Equivalent resistance (R) of these 3 resistors can be calculated as:

1 / R = 1 / 1 + 1 / 2 + 1 / 3 = 11 / 6

⇒ R = 6 /11

We can clearly observe that 6 / 11 is lesser than 1.

Hence, option (a) is the correct answer.

Hope you found the answer helpful!!

Regards!!

Answer 2

Given :

R₁  = 1 ohm

R₂ = 2 ohm

R₃ = 3 ohm

To Find :

The combined resistance of the three resistors

Solution :

Given, the resistors are connected in parallel combination.

We are required to find the equivalent resistance of the three resistors connected in parallel.

Let the equivalent resistance be 'R'

∴    $\frac{1}{R}$ =  $\frac{1}{1}$ + $\frac{1}{2}$ + $\frac{1}{3}$

⇒   $\frac{1}{R}$ =  $\frac{6 + 3 + 2}{6}$

⇒   $\frac{1}{R}$ = $\frac{11}{6}$

∴    R = $\frac{6}{11}$ = 0.545 ohm

Hence, the equivalent resistance (R) is 0.545 ohm.

As R < 1Ω ,

Thus, Option (a) is correct.