Question

Three resistors of 1 Ω, 2Ω and 3 Ω are connected in parallel. The combined resistance of the three resistors should be

Answer 1

Explanation:

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Answer 2

$\large\maltese \: \underline{ \pmb{ \frak{ Parallel \: Connection \: of \: resistors: - }}}$

• When two or more resistors are connected parallely and have a coinciding terminal points, then they are said to be connected in parallel.

$\large\maltese \: \underline{ \pmb{ \frak{ Solution: - }}}$

• In this question, we are provided with 3 resistors that are connected in parallel and we are asked to calculate the equivalent resistance.
• This problem can be fixed by using the following formula:-

$\\ \large \qquad \dag\underbrace{ \frak{ \purple{Equivalent \: Resistance \: In \: Parallel : - }}}$

$\\ \quad \qquad \quad \bigstar\underline{ \boxed{ \bf \pink{ \frac{1}{R_{(eq)} } = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} . \: . \: . }}} \bigstar$

$\underline{ \sf Substitute \: the \: values \: in \: formula \: we \: get : - }$

$\\ \quad \qquad \quad : \implies \sf \frac{1}{R_{(eq)} } = \frac{1}{1} + \frac{1}{2} + \frac{1}{3}$

$\\ \quad \qquad \quad : \implies \sf \frac{1}{R_{(eq)} } = \dfrac{6 + 3 + 2}{6}$

$\\ \quad \qquad \quad : \implies \sf \frac{1}{R_{(eq)} } = \dfrac{11}{6}$

$\\ \quad \qquad \quad : \implies \boxed{\boxed{\sf \orange{ R_{(eq)} = \dfrac{6}{11} \: Ømega}}} \bigstar$

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