Question

Three resistors of 1 Ω,2Ω and 4Ωare connected in parallel in circuit.if a 1 Ω resistor draws a current of 1A find the current through the other two resistor.​

Answer 1

Answer :

• The current through 2 Ω resistor = 0.5 A
• The current through 4 Ω resistor = 0.25 A

Explanation :

Given,

• Three resistors of 1 Ω,2Ω and 4Ωare connected in parallel in circuit
• 1 Ω resistor draws a current of 1A

To find,

• the current through the other two resistors

Solution,

In parallel connection,

⮞ the total current is the sum of the currents flowing through each resistor.

⮞ the voltage across each resistor is same.

Let

• R₁ = 1 Ω

• R₂ = 2 Ω

• R₃ = 4 Ω

Let the current through 1 Ω, 2 Ω and 4 Ω be I₁ , I₂ and I₃ respectively and voltage be "V"

⇒ I₁ = 1 A (Given)

★ Ohm's law,

V = IR

★ First resistor,

R₁ = 1 Ω

I₁ = 1 A

➟ V = I₁R₁

V = (1)(1)

V = 1 V

★ Second resistor,

R₂ = 2 Ω

V = 1 V

I₂ = ?

➟ V = I₂R₂

  1 = I₂ × 2

  I₂ = 1/2

  I₂ = 0.5 A

★ Third Resistor,

R₃ = 4 Ω

V = 1 V

I₃ = ?

➟ V = I₃R₃

1 = I₃ × 4

I₃ = 1/4

I₃ = 0.25 A

Therefore,

• The current through 2 Ω resistor = 0.5 A
• The current through 4 Ω resistor = 0.25 A

Answer 2

Answer :

The current through 2 Ω resistor = 0.5 A

The current through 2 Ω resistor = 0.5 AThe current through 4 Ω resistor = 0.25 A

Explanation :

Given,

Three resistors of 1 Ω,2Ω and 4Ωare connected in parallel in circuit

1 Ω resistor draws a current of 1A

To find,

the current through the other two resistors

Solution,

In parallel connection,

⮞ the total current is the sum of the currents flowing through each resistor.

⮞ the voltage across each resistor is same.

Let

R₁ = 1 Ω

R₂ = 2 Ω

R₃ = 4 Ω

Let the current through 1 Ω, 2 Ω and 4 Ω be I₁ , I₂ and I₃ respectively and voltage be "V"

⇒ I₁ = 1 A (Given)

★ Ohm's law,

V = IR

★ First resistor,

R₁ = 1 Ω

I₁ = 1 A

➟ V = I₁R₁

V = (1)(1)

V = 1 V

★ Second resistor,

R₂ = 2 Ω

V = 1 V

I₂ = ?

➟ V = I₂R₂

  1 = I₂ × 2

  I₂ = 1/2

  I₂ = 0.5 A

★ Third Resistor,

R₃ = 4 Ω

V = 1 V

I₃ = ?

➟ V = I₃R₃

1 = I₃ × 4

I₃ = 1/4

I₃ = 0.25 A

Therefore,

The current through 2 Ω resistor = 0.5 A

The current through 2 Ω resistor = 0.5 AThe current through 4 Ω resistor = 0.25 A

Hope it helps you♥️♥️