Question

three resistors of 13ohom, 17 ohom & 10 ohom are connected in series. combination. voltes 30 then find current ​ ​

Answer 1

$\huge\sf\pink{Answer}$

☞ Current = 0.75 A

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$\huge\sf\blue{Given}$

✭ Three resistors of 13Ω,17Ω & 10Ω are connected in series

✭ Potential difference = 30 V

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$\huge\sf\gray{To \:Find}$

◈ The current through the circuit?

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$\huge\sf\purple{Steps}$

$\large\underline{\underline{\sf Concept}}$

Here we shall first find the net resistance of the circuit and then after that we shall use the Ohm's law to find the current in the circuit

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The net Resistance of a series connection is given by,

$\underline{\boxed{\sf R_{net} = R_1+R_2+R_3...R_n}}$

Substituting the given values,

➝ $\sf R_{net} = R_1+R_2+R_3$

➝ $\sf R_{net} = 13 + 17 + 10$

➝ $\sf \orange{R_{net} = 40 \Omega}$

So now we shall use the current through the circuit with the help of Ohm's law, that is,

$\underline{\boxed{\sf V=IR}}$

Substituting the required values,

➳ $\sf V=IR$

➳ $\sf 30 = I \times 40$

➳ $\sf 30 = 40I$

➳ $\sf \dfrac{30}{40} = I$

➳ $\sf \orange{I = 0.75 \ A}$

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