three resistors of 13ohom, 17 ohom & 10 ohom are connected in series. combination. voltes 30 then find current
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Answered by
0
Answer:
this ans was preated to in
Answered by
1
Answer:
Answer is 0.75
Explanation:
In series combination
R effective=R1+R2+R3
Reff=17+13+10===40 ohm
According to ohms law. V=IR
here v=30 V
then, I=V/R--->I=30/40=3/4=0.75
Ans =0.75 A
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