Question

Three resistors of 1ohm,2ohm and 3ohm are connected in parallel.The combined resistance

Answer 1

Given ,

The three resistor 1 ohm , 2 ohm and 3 ohm are connected in parrallel combination

We know that ,

The equivalent resistance in parrallel combination is given by

$\large \sf \fbox{ \frac{1}{R} = \frac{1}{ R_{1}} + \frac{1}{ R_{2}} + .. + \frac{1}{ R_{n}} }$

Thus ,

$\sf \mapsto \frac{1}{R} = \frac{1}{1} + \frac{1}{2} + \frac{1}{3} \\ \\\sf \mapsto \frac{1}{R} = \frac{6 + 3 + 2}{6} \\ \\\sf \mapsto R = \frac{6}{11} \\ \\\sf \mapsto R = 0.54 \: \: ohm$

$\therefore \sf \underline{The \: combined \: resistence \: is \: 0.54 \: ohm }$

Answer 2

${ \large{ \bold{\underline{ \underline{ \red{Given:-}}}}}}$

Three resistors of 1 ohm,2 ohm and 3 ohm are connected in parallel.

${ \large{ \bold{\underline{ \underline{ \blue{To \: Find:-}}}}}}$

The combined resistance

Concept:-

The equivalent resistance in parallel combination is

$\mapsto\boxed{\tt{\pink{\frac{1}{R} = \frac{1}{R_1}+\frac{1}{R_2}...+\frac{1}{R_n}}}}$

${ \large{ \bold{\underline{ \underline{ \green{Calculation:-}}}}}}$

$\large\mapsto{\tt{\frac{1}{R} = \frac{1}{1}+\frac{1}{2}+\frac{1}{3}}}$

$\large\mapsto{\tt{\frac{1}{R} = \frac{6+3+2}{6}}}$

$\large\mapsto{\tt{\frac{1}{R}= \frac{11}{6}}}$

$\large\mapsto{\tt{\frac{1}{R}= \frac{6}{11}}}$

$\large\mapsto{\tt{R= 0.54 0hm}}$

The combined resistance is 0.54 0hm.