Question

three resistors of 1ohm,2ohm and 3ohm are connected in parallel. The combined resistance of the three resistors should be
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Answer 1

Answer:

1/Rp = 1/1 + 1/2 + 1/3

LCM = 6

1/Rp = (6 + 3 + 2) / 6

1/Rp = 11/6

Rp = 6/11

Rp = 0.54 ohm

Therefore, combined resistance is 0.54 ohm.

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Answer 2

Answer:

as the resistance is connected in parallel then the sum of the RECIPROCATE of all the three resistances would equal to the sum of the combination of resistance hence,

1/Rp=1/R1+1/R2+1/R3

" =1/1+1/2+1/3

" =6+3+2/6 (as the lcm is 6)

1/Rp=11/6

Rp=0.54 ( since we reciprocated it in order to get the value of Rp)

if u have any doubt feel free to comment below.

in the last step i divided 6 by 11

THANKS!