Question

Three resistors of 2 Ω ,3Ω and 6Ω are given.what is highest resistance that you can get using all of then.what is least resistance that you can get using all of them.can you make a resistance 4.5Ω using these three? draw circuit​

Answer 1

Explanation:

We know that, minimum resistance means the resistors are connected in parallel and when they are connected in series the resistance become more.

So according to the question,

Highest resistance :-

$R = R_1 + R_2 + R_3$

$R = 2 + 3 + 6$

$\boxed{R = 11Ω}$

Minimum resistance:-

$\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}$

$\frac{1}{ R} = \frac{1}{2} + \frac{1}{3} + \frac{1}{6}$

$\frac{1}{R} = \frac{3 + 2 + 1}{6}$

$\frac{1}{R} = \frac{6}{6}$

$\boxed{R = 1Ω}$

No we can't make 4.5 Ω resistance using the given inputs.