Science, asked by muralimini02, 10 months ago

Three resistors of 2 ohm,3 ohm,and 6 ohm are connected (1) series (2) parallel.Calculate the ratio of the effective resistance of series and parallel combination of resistance.

Answers

Answered by shivamkumar188012
2

Answer:

i cannot know answer so iam not help you

Answered by supriths4804
12

Answer:

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Explanation:

R=2ohm, 3ohm, 6ohm

R(s)=R1+R2+R3

=2+3+6

=11ohm

Resistance in series is 11 ohm

1/R(p)=1/R1+1/R2+1/R3

1/R(p)=1/2+1/3+1/6

1/R(p)=(3+2+1)/6

1/R(p)=6/6

1/R(p)=1

R(p)=1

Resistance in parallel is 1 ohm.

Ratio of resistance in series and resistance in parallel is 11:1.

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