Question

Three resistors of 2ohm ,3ohm ,6ohm are given in the class a)what is the highest resistance that you can get using all of them

Answer 1

Answer:

The highest resistence we can get using all of the above resistors is by making a series combination of them.

Explanation:

Here we go,

R(eq) = R1 +R2+R3 (In series combination)

= 2+3+6

= 11 ohm (ANSWER)

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Answer 2

"$\bf{ \pmb{ \underline{\gray{GIVEN}}}} \\ \sf \: \small{ Three \: resistors \: of \: 2 Ω, 3 Ω \: and \: 6 Ω \: are \: given \: respectively. }\\ \\ \\ \bf{ \pmb{ \underline{\gray{TO \: FIND }}}}\\ \rm \small{Least \: value \: of \: the \: three \: resistances. }\\ \\ \\ \bf { \pmb{ \underline{\gray{ SOLUTION}}}} \\ \tt \tiny{For \: the \: max \: value \: of \: the \: resistances, resistor \: are \: connected \: in \: \bf{\blue{Series \: Combination}} }\\ \tt \tiny{For \: the \: least \ value\ of \: the \: resistances, resistor \: are \: connected \: in\ \bf{\green{Parallel \: Combination}} } \\ \\ \cal \: \small{\red{Connect \: the \: resistor \: in \: parallel \: for \: getting \: least \: value :} }\\ \\ \begin{gathered}\small \rm R_{eq}= {R_1} + {R_2} + {R_3} \\ \\ \small \rm R_{eq} = 2+3+6 \\ \\ \large { \boxed{\bf \blue{R_{eq} = 11\ Ω}}}\end{gathered}$