Question

Three resistors of 3,4 and 5 ohms are joined in parallel in an electric circuit. If a current of 150 mA flows through the resistor of 4 ohms, then calculate the values of the current in mA which will be flowing through the other two resistors

Answer 1

R = 1/R1 + 1/R2 + 1/R3

R = 1/3+1/4+1/5

R = (20+15+12)/60

R = 47/60

I1 = V/R1

150/1000 = V/4

V = 60/100

V = 6/10

V = IR

6/10 = 47/60I

I = 47/100

I = I1+ I2 +I3

I - I1 = I2 +I3

I2 +I3 = 47/100 -15/100

I2 +I3 = 32/100