three resistors of 3 ohm each are connected to a battery of 3 v as shown
Attachments:
deanne06:
Please answer this!
Answers
Answered by
2
a. consider the 2 resistors in series: Rs = R1 + R2 = 3+3 = 6 ohm
now consider the parallel resistor : 1/Rp = 1/R1+1/R2 = 1/6 + 1/3
take LCM = (1+2)/6 = 3/6= 1/2 = 0.5 ohm
effective resistance Rt = Rs +Rf = 6 + 0.5 = 6.5 ohm
b. V = IR
I = V / R = 3 / 6.5 = 0.5 A (approx)
Similar questions