Three resistors of 30 ohm each are connected such that equivalent resistance is 10 ohm. Then
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They must be connected in parallel
They must be connected in series
Two may be connected in parallel and in series with third
O
Two may be connected in series and in parallel with third
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Answer:
They must be connected in Parallel
Explanation:
when we do in series
GIVEN :
R = 30 OHM
CASE 1 IN SERIES :
FORMULA FOR RESISTOR'S IN SERIES : R1+R2+ R3 +.... = RS
WHERE RS IS TOTAL RESISTANCE
SO 30+30+30 = 90 OHM
CASE 2 IN PARALLEL :
FORMULA FOR RESISTOR'S IN PARALLEL: 1/R1+1/R2+ 1/R3 +.... = 1/RS
WHERE RS IS TOTAL RESISTANCE
WHERE RS IS TOTAL RESISTANCESO 1/30+1/30+1/30 = 3/30 OHM
ON SIMPLIFICATION WE GEY 3/30 = 1/10
ACCORDING TO TOTAL PARALLEL RESISTANCE ANSWER SHOULD BE RECIPROCALED
SO THERE FOR ANSWER IS 10 OHM
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