Question

Three resistors of 5 Ω,10Ω and 15 Ω are connected in series and the combination is connected to battery of 30V. Ammeter and voltmeter are connected in the circuit.draw a circuit diagram to connect all the devices in proper correct order.what is the current flowing and potential difference across 10 Ω resistance?

Answer 1

Equivalent resistance equal to 5 + 10 + 15 Ohm= 30 ohm I=V/R I=30/30 I=1A Current through 10 ohm resistor will remain same that is equal to the total current in the circuit because the  resistor is connected in series Now potential difference in the 10 ohm resistor V=IR V=1*10 V=10V

Answer 2

Answer:

The potential difference across 10 ohm resistor is 10 volt.

Explanation:

Given that,

Three resistors are connected in series.

R₁=5 ohm

R₂ =10 ohm

R₃ =15 ohm

Voltage V = 30 V

We need to calculate the resistance

$R = R_{1}+R_{2}+R_{3}$

$R =5+10+15$

$R=30\ Omega$

We need to calculate the current in the circuit

Using ohm's law

The current is directly proportional to the voltage.

$V = I R$

Where, I = current

V = voltage

R = resistance

Put the value into the formula

$30=I\times30$

$I = 1\ A$

Current through 10 ohm resistor will remain same that is equal to the total current in the circuit because the resistor is connected in series.

The potential difference across 10 ohm resistance,

$V =IR$

$V=1\times10$

$V = 10\ V$

Hence, The potential difference across 10 ohm resistor is 10 volt.