Three resistors of 5 ohm,10ohm,15ohms are connected in series and the combination is connected to the battery of 30V. Ammeter and Voltmeter are connected in the circuit. Draw a circuit diagram to connect all the devices in proper correct order. What is the current flowing and potential l difference across 10 ohm resistance?
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by ohms law
V=IR
30=I(R1+R2+R3)
30=I(5+10+15)
30=I(30)
30/30=I
1A=I
since the resistors are in circuit current will be same.
poten difference across 10 ohm resitor-
by ohms law
V =IR
V=1*10
V=10V
V=IR
30=I(R1+R2+R3)
30=I(5+10+15)
30=I(30)
30/30=I
1A=I
since the resistors are in circuit current will be same.
poten difference across 10 ohm resitor-
by ohms law
V =IR
V=1*10
V=10V
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