Question

Three resistors of 5 omh,10 omh and 15 omh are connected in series with a 12 V power supply. Calculate their combined resistance, the current that flows in the circuit and in each resistor and the potential difference across each resistor.​

Answer 1

1)As the resistors are in series, So equivalent resistance,

R= 5+10+15 =30 ohm.

2) Current in the circuit ,I= V/ R

= 12/30. =0.4 Amperes

3) I in 5ohm resistance= V/R1

=12/ 5. =2.4 A

In 10 ohm resistance= 12/10

= 1.2 ampere

In 15 ohm resistance = 12/15

= 0.8 ampere

4) Potential difference across 5ohm resistor=I R1

=0.4 ❌ 5. =2 volt

Across 10 ohm resistor=I R2

= 0.4 ❌10 =4volt

Across 15 ohm resistor= I R 3

= 0.4❌ 15. = 6 volt

Thank you! and is waiting for more questions.

I hope you shall become a good human in your life.

Answer 2

Answer:

For resistance in Series, 5 + 10 + 15 = 30 ohms will be total resistance. Current in the circuit will be constant. As V = IR, I = V/R and I = 12/5 = 2.4A