Question

Three resistors of 6 Ω, 2 Ω and x are connected in series, to a cell of e.m.f.3/2 V, when the current registered in the circuit is1/6 A. Draw the circuit diagram and calculate the value of x.

Answer 1

Answer:

R=R1+R2+R3

R=6+2+x

R=8+x

Then,

V=IR

3/2=1/6+8+x

3/2=1+48+6x/6

3×6/2=49+6x

9=49+6x

9-49=6x

-40=6x

-40/6=x

-20/3=x