three resistors of 6 ohm 2 ohm and X are connected in series to a cell of end 1.5volt the current regesterd is 1/6 ampere caluculate the value of X {final answer [1 ohm]}
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Answer:
Explanation:
Equivalent resistance in series as= 6+2+x
= 8+x
Now by ohm's law
V= iR
1.5= 1/6× 8+x
simply solve
9= 8+x
x= 1 Ohm Ans
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