Question

Three resistors of 6 ohm 3 ohm and 2 ohm are connected in parallel this combination of resistors are connected to another resistor of 4 ohm and then to a cell of EMF 1.5 volt draw the circuit diagram and calculate the current drawn from the cell.​

Answer 1

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R1=3ohm R2=4ohm,R3=6ohm

• As the resistors are connected in parallel

1/Rtotal=1/3+1/4+1/6

1/Rtotal=(4+3+2)/12

1/Rtotal=9/12

Rtotal=12/9

Rtotal=4/3 ohm

Total current=Voltage /Rtotal

Itotal=2/(4/3)

Itotal=6/4

Itotal=3/2 Ampere

• For resistance in the parallel ,voltage across each resistor is same and total current is sum of current through each resistor.

Current through R1=V/R1=2/3 Ampere

Current through R1=V/R2=2/4=1/2Ampere

Current through R1=V/R3=2/6=1/3Ampere

Total current is 3/2 Ampere

Answer 2

Explanation:

R1 = 6, R2 = 3, R3 = 2.

1/R = 1/6+1/3+1/2

= 1+3+2/6

= 6/6 = 1

R = 1 ohm

R +R4 = 1+4 = 5 ohm

I = V/R

= 1.5/5

= 0.3 A