Three resistors of 6ohm 8ohm and 12ohm are connected in parallel.The potential difference of 5v is applied across the circuit. Find the total current flowing in the circuit
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Since the resistors are connected in parallel
R1= 6 ohm R2= 8 ohm R3=12 ohm
1/Rtotal =1/R1+1/R2+1/R3
=1/6+1/8+1/12=9/24
R total =24/9
We know V=IR
V=5 V
I=V/R
=5×9/24
=1.85 A
jakebiniojacob:
ITS WRONG YOU DID NOT TAKE THE RECIPROCAL OF 9/24
IT WAS SUPPOSED TO BE=>5*24/9
Read it again ..I guess u got it wrong ..r is 24/9
And I took reciprocal ..so it changed to 9/24
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- Given: Resistors of 6ohm,8ohm and 12ohm
- Battery=5V
We know that resistors in parallel => 1/Rp=1/R1+1/R2+1/R3
=>1/Rp=1/6+1/8+1/12
=>8+6/48 + 1*4/12*4
=>14/48 + 4/48
=>18/48 (cut by 2 and 3)
=>3/8
∴ R=3/8
Since V=IR
we'll get that, I=V/R
I=5/3/8
=>5*8/3 (taking Reciprocal)
=>40/3A
Therefore, CURRENT(I)=40/3A
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