Question

Three resistors, of 8.0 ohms, 12 ohms, and 24 ohms, are in parallel, and a current of 20 A is drawn by the combination. Determine (a) the potential difference across the combination and (b) the current through each resistance.

Answer 1

Answer:

potential difference=80ohm

current=10A ,20/3A, 10/3A

Answer 2

Answer:

In this question, we have been asked to find the potential difference across the given combination as well as current through each resistance.

Explanation:

Given: Value of resistances, R₁ = 8 Ω, R₂ = 12 Ω and R₃ = 24 Ω.

           Current being = 20 A

To Find:

1. Potential difference across the combination.
2. Current through each resistance.

Now, for the 1. part:

We have to find Potential difference across the system.

We know that,                        V = IR

where, V = potential difference, I = total current and R = total resistance.

As this is a parallel combination, current will be distributed in each branch and potential will remain same.

Hence,    V = 20 × (8+12+24)

               V = 20 × 44

               V = 880 Volts

Now, 2. part:

We have to find current across each branch.

We know,                                  $I = \frac{V}{R}$

Hence,                        $I_{1} = \frac{V}{R_{1} } , I_{2} = \frac{V}{R_{2} } , I_{3} = \frac{V}{R_{3} }$

Therefore, I₁ = $\frac{880}{8}$

                    = 110 A

                  I₂ = $\frac{880}{12}$

                    = 73.3 A

                  I₃ = $\frac{880}{24}$

                      = 36.5 A