Question

Three resistors of resistances 4 Ω, 6 Ω, and 12 Ω be connected to give a total resistance of 8 Ω,
1) I AND II ARE SERIES AND III IN PARALLEL
2) II AND III ARE IN SERIES AND I IN PARALLEL
3) I AND II ARE PARALLEL AND III IN SERIES
4) II AND III ARE IN PARALLEL AND I IN SERIES
5) NONE OF ABOVE​

Answer 1

Answer:

5 none of the above

Explanation:

because non is in seires

Answer 2

Answer:

4) II AND III ARE IN PARALLEL AND I IN SERIES

Explanation:

Using the equation for resistors in parallel and in series.

Parallel Resistors (6Ω and 12Ω)

R2&3 = 1/(1/6+1/12) = 4Ω

Series Resistors

Add the 4Ω from the R2&3;

Rtotal = R1 + R2&3

Rtotal = 4Ω + 4Ω

Rtotal = 8Ω

Hence, 4) II AND III ARE IN PARALLEL AND I IN SERIES.