Question

Three resistors of resistances 5 ohm, 3 ohm and 2
ohm are connected in series with 10 V battery.
Calculate their effective resistance and the current
flowing through the circuit.

Answer 1

Answer:

effective resistance= R1+R2+R3

=5+3+2=10 Ohm

now V=IR

I=V/R

=10/10

I=1 Ampere

Answer 2

Answer:

R=10. I=1

Explanation:

formula for connecting in series commination is R1+R2+R3=R

5+3+2= 10 total resistance

V=IR current in the circuit

10=I*10

I=10/10

I=1