Physics, asked by Himajabaskaran, 10 months ago

Three resistors of value 30ohm,10ohm and 5ohm are connected in parallel across a voltage source of 6v . Calculate the total equivalent resistance of the circuit and the current through each resistor.

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Answered by kikibuji
5

Answer:

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Answered by Anonymous
19

Given that, hree resistors of value 30ohm,10ohm and 5ohm are connected in parallel across a voltage source of 6v.

Let's denote 30 ohm resistor by R1, 10 ohm resistor by R2 and 5 ohm resistor by R3.

-----------| R1 |---------- (R1 = 30 ohm)

-----------| R2 |---------- (R2 = 10 ohm)

-----------| R3 |---------- (R3 = 5 ohm)

------------| V |----------- (V = 6V)

We have to find the total equivalent resistance of the circuit and the current through each resistor.

a) As, all are connected in parallel. So,

1/Rp = 1/R1 + 1/R2 + 1/R3

1/Rp = 1/30 + 1/10 + 1/5

1/Rp = (1 + 3 + 6)/30

1/Rp = 10/30

1/Rp = 10/30

Rp = 3

Req = Rp

Req = 3 ohm

Therefore, the equivalent resistance of the circuit is 3 ohm.

b) In second part we have to find the current through each resistor.

From ohm's law, we can say that

I = V/R

I = 6/3 = 2A

The net current flowing through the circuit is 2A.

For 30 ohm resistor i.e. R1

I1 = 6/30 = 0.2 A

For 10 ohm resistor i.e. R2

I2 = 6/10 = 0.6 A

For 5 ohm resistor i.e. R3

I3 = 6/5 = 1.2 A

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