Question

Three resistors of values 2 Ω, 4 Ω, and 6 Ω are connected in series. Find the equivalent resistance of combination of these resistors. ​

Answer 1

Answer:

12oms

Explanation:

2+4=6

6+6=12

so the answer is 12oms

Answer 2

answer

R

eq

=R

1

+R

2

+R

3

(In series)

=2Ω+4Ω+6Ω

=12Ω

Here is your answer bro