Question

three resistors of values 2ohm,4ohm,6ohm connected in parallel.the equivalent resistance of combination of resistors is​

Answer 1

Given:-

• Resistance,R1 = 2 ohm

• Resistance ,R2 = 4 ohm

• Resistance ,R3 = 6 ohm

To Find:-

• Equivalent Resistance of combination of resistors ,R eq.

Solution:-

By using this Formula

• 1/Req = 1/R1 + 1/R2 +1/R3

Substitute the value we get

→ 1/Req = 1/2 +1/4 +1/6

→ 1/Req = 6 + 3 +2/12

→ 1/Req = 11/12

→ Req = 12/11

→ Req = 1.09 Ω

Therefore, the equivalent Resistance in the resistor is 1.09 Ohms.

Additional Information!!

•Potential Difference: The potential difference between two point in an electric circuit carrying some current as the work done to move a unit charge from one point to the other.

Potential difference = Work done /Charge.

V = W/Q

here

V is the potential difference

W is the work done

Q is the charge

• SI unit of electric potential energy is volt (V).

• 1 volt : The potential difference between two points in a current carrying conductor when one joule of work is done to move a charge of one coulomb from one point to other.

• 1 Volt = 1Joule/1Coulomb

Answer 2

Solution

Given,

• R1 = 20ohm
• R2=40ohm
• R3 = 60 ohm

To find ,

• equivalent resistance of combination of resistors .

We know that :

1/req = 1/r1+1/r2+1/r3

now putting the value we get ;

$= > \frac{1}{req} = \frac{1}{2} + \frac{1}{4} + \frac{1}{6} \\ = > 6 + 3 + \frac{2}{12}$

$= > \frac{1}{r \: eq} = \frac{11}{12}$

$= > r \: eq \: = \frac{12}{11}$

$\bold {= > r \: eq \: = 1.09}$

The resistance equivalent is 1.09ohm .