Question

three resistors of values 6 ohms, 9 ohms and 18 ohms are connected in parallel with a 9v battery . find equivalent resistance current through each resistors and net current... pls help me with correct explanation

Answer 1

PL4EASE REFER THE ATTACHMENT BELOW

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Answer 2

Answer

• Current , I = 3 Amperes

Given

• Three resistors of values 6 ohms, 9 ohms and 18 ohms are connected in parallel with a 9 v battery

To Find

• Net current

Solution

When the resistances are connected in parallel ,

$\bf \dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}+...$

Here ,

$\bf R_1=6\ \Omega\\\\\bf R_2=9\ \Omega\\\\\bf R_3=18\ \Omega$

$\implies \bf \dfrac{1}{R_{eq}}=\dfrac{1}{6}+\dfrac{1}{9}+\dfrac{1}{18}\\\\\bf \implies \dfrac{1}{R_{eq}}=\dfrac{1}{6}+\dfrac{1}{6}\\\\\implies \bf R_{eq}=3\ \Omega$

Voltage , V = 9 V

Now , Apply Ohm's law ,

$\implies \bf V=IR_{eq}\\\\\implies \bf 9=I(3)\\\\\implies \bf I=3\ Amperes$

So , net current is 3 Amperes