Question

Three resistors R1, R2, and R3 are connected in series with a constant voltage source of V volts. The voltage across R1 is 4 V power loss in R2 is 16W and the value of R3 is 6 Ω. If the current flowing through the circuit is 2 A find the voltage V?

Answer 1

Explanation:

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Answer 2

Answer:

I = 2

∴ 2R₁ = 4                ⇒ R₁ = 2

2² R₂ = 16             ⇒ R₂ = 4

R₃ = 6

∴ V = 2( R₁+R₂+R₃) = 2× 12 = 24  (v)

Explanation: