Three resistors R1, R2 and R3 have the values 5 Ω, 10 Ω, 30 Ω, respectively
are connected in parallel which have been connected to a battery of 12 V.
Calculate (i) the current through 10 Ω resistor,
(ii) the total circuit resistance.
(iii) total current in the circuit. 5 marks
Answers
Answer:
V=12V
R1, R2 and R3 are connected in parallel.
(a) Current through R1 = V/R1 = 12/5 = 2.4 A
Current through R2 = V/R2 = 12/10 = 1.2 A
Current through R3 = V/R2 = 12/30 = 0.4 A
(b) Total current in the circuit = 2.4 + 1.2 + 0.4 = 4 A
(c) Total resistance in the circuit=R
1/R = 1/R1+ 1/R2 + 1/R
1/R = 1/5 + 1/10 + 1/30
1/R = 10/30
R = 3 ohm
Explanation: PLEASE MAKE ME THE BRAINLEIST
Answer:
V=12V
R1, R2 and R3 are connected in parallel.
(a) Current through R1 = V/R1 = 12/5 = 2.4 A
Current through R2 = V/R2 = 12/10 = 1.2 A
Current through R3 = V/R2 = 12/30 = 0.4 A
(b) Total current in the circuit = 2.4 + 1.2 + 0.4 = 4 A
(c) Total resistance in the circuit=R
1/R = 1/R1+ 1/R2 + 1/R
1/R = 1/5 + 1/10 + 1/30
1/R = 10/30
R = 3 ohm
PLEASE MAKE ME THE BRAINLEIST