Three resistors with resistances 5om ,10om, 15om are connect in parallel to a 20v battery. What is the current through the circuit
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Explanation:1/R(eq) =(1/5)+(1/10)+(1/15) =11/30. R(eq)=30/11. I=V/R(eq) I=20/(30/11).
I=7.33(approx.). Hope this helps✌️✌️And mate please mark me as brainliest
Answered by
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Since the resistors are connected in parallel, So net resistance, Rn
1/Rn = 1/R1 + 1/R2 + 1/R3
R1 = 5 ohm
R2 = 10 ohm
R3 = 15 ohm
1/Rn = 1/5 + 1/10 + 1/15
= (6 + 3 + 2)/30
1/Rn = 11/30
Rn = 30/11 ohm
Now, V = IR
So, Current, I = V/Rn
where V = 20 Volt (given)
I = 20/(30/11)
= (20 * 11)/30
= 22/3
I = 7.333 ampere
Thankyou!!!
1/Rn = 1/R1 + 1/R2 + 1/R3
R1 = 5 ohm
R2 = 10 ohm
R3 = 15 ohm
1/Rn = 1/5 + 1/10 + 1/15
= (6 + 3 + 2)/30
1/Rn = 11/30
Rn = 30/11 ohm
Now, V = IR
So, Current, I = V/Rn
where V = 20 Volt (given)
I = 20/(30/11)
= (20 * 11)/30
= 22/3
I = 7.333 ampere
Thankyou!!!
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