Question

three right circular cylinder of same height and radius 6cm 8cm and 10cm respectively article the first two smaller cylinders are filled with sand when sand is poured into smaller cylinders gas cylinder will it be completely filled with sand explain your answer and show the Pythagoras theorem can be extended for right circular cylinder

Answer 1

Answer:

solved

Step-by-step explanation:

the volume of the two smaller cylinders = πh(6²+8²) = 100πh

the volume of the BIG cylinder = πh(10²) = 100πh

true - thy are equal

therefore

πh(6²+8²) = πh(10²)  which is an other extension for the Pythagorian theorem.

Answer 2

Volume of two small cylinder=Volume of large cylinder

Step-by-step explanation:

Radius of one cylinder=$r_1=6 cm$

Radius of second cylinder=$r_2=8 cm$

Radius of third  cylinder=$r_3=10 cm$

Let h be the height of each cylinder

We know that

Volume of cylinder=$V=\pi r^2 h$

Where r=Radius of cylinder

h=Height of cylinder

By using the formula

Volume of large cylinder=$\pi(r_3)^2 h=\pi (10)^2h=100\pi h$

Volume of two small cylinder$=\pi h(r^2_1+r^2_2)$

Volume of two small cylinder$=\pi(r^2_1+r^2_2)h$

Volume of two small cylinder$=\pi (6^2+8^2)h=100\pi h$

Volume of large cylinder= volume of two small cylinder

$100\pi h=\pi (6^2+8^2)h$

Pythagoras theorem

$(Hypotenuse)^2=(base)^2+(perpendicular\;side)^2$

Hence, Pythagoras theorem can be extended for right circular cylinder.

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