Question

Three rings each having equal radius r are placed mutually perpendicular to each

Answer 1

It seems you haven't written the whole QUESTIONS,

So, Three rings each having equal radius R, are placed mutually perpendicular to each other and each having its centre at the origin of coordinate system If current I is flowing through each ring them the magnitude of the magnetic field at the common centre is:

Now,

we know,

B for circular loop = ui/2r. This formula is for the magnetic field at the center of a circular loop of current.

So,

$\mathit{\large{\vec{B} = \vec{B_x} + \vec{B_y} + \vec{B_z}}}\\ \\ \mathit{\large{\vec{B} = \frac{u_oI}{2R} + \frac{u_oI}{2R} + \frac{u_oI}{2R} }}\\\\\mathit{\large{ |\vec{B}| = \sqrt{3} \frac{u_oI}{2R} }}$

Answer 2

Step-by-step explanation:

here is the answer for you dear