Question

Three ropes of length ½ m,⅗m and ⅓ m are joined end. what is the length of the new rope formed?​

Answer 1

Answer:The given three ropes are 7m, 12 m 95cm and 3m85cm long. We know that 1m=100cm, therefore,

The length of the respective ropes will be:

1st rope =7×100=700cm

2nd rope =(12×100)+95=1200+95=1295cm

3rd rope =(3×100)+85=300+85=385cm

Now, let us factorize the length of the ropes as follows:

700=2×2×5×5×7

1295=5×7×37

385=5×7×11

The highest common factor (HCF) is 5×7=35

Hence, the greatest possible length that can be used to measure these ropes is 35cm.

Step-by-step explanation:

Answer 2

Answer:

1/2 + 3/5+ 1/3= 1 13/30

Step-by-step explanation:

Lcm= 2×3×5=30

=1×15+3×6+1×10/30=15+18+10/30

=43/30=1 13/30